Let be a mapping from a topological space onto a topological space . If is a perfect map and is a Lindelof space, then so is . If is a closed map and is a paracompact space, then so is . In other words, the pre-image of a Lindelof space under a perfect map is always a Lindelof space. Likewise, the pre-image of a paracompact space under a closed map is always a paracompact space. After proving these two facts, we show that for any compact space , the product is Lindelof (paracompact) for any Lindelof (paracompact) space . All spaces under consideration are Hausdorff.
Another way to state the above two facts is that Lindelofness is an inverse invariance under perfect maps and that paracompactness is an inverse invariance of the closed maps. In general, a topological property is an inverse invariance of a class of mappings if the following holds: for any mapping belonging to , if has the property, then so does . In contrast, a topological property is an invariance of a class of mappings if for any mapping belonging to , if has the property, then so does .
All mappings under consideration are continuous maps. A mapping , where , is a closed map if for any closed subset of , is closed in . A mapping , where , is a perfect map if is a closed map and that the point inverse is compact for each .
Perfect mappings and closed mappings are objects with strong properties. Such a map places a restriction on what topological properties the “domain” space or the “range” space can have. The theorems below indicate that it is not possible to map a non-Lindelof space onto a Lindelof space using a perfect map and that it is not possible to map a non-paracompact space onto a paracompact space using a closed map. On the other hand, it is not possible to map a separable metric space onto a separable but non-metric space using a perfect map (see here). We prove the following theorems.
Theorem 1…. Lindelofness (or the Lindelof property) is an inverse invariant of the perfect maps.
Theorem 2 ….Paracompactness is an inverse invariant of the closed maps.
Lemma 3 …. Let be a closed map with . Let be an open subset of . Define . Then the set is open in and that .
For the proof of Lemma 3, see Lemma 2 here.
Proof of Theorem 1
Let be a perfect map with . Suppose is Lindelof. Let be an open cover of . Without loss of generality, we can assume that is closed under finite unions. For each , define . By Lemma 3, each is an open subset of . We claim that is an open cover of . To this end, let . Since is a perfect map, the point inverse is compact. As a result, we can find a finite such that . Since is closed under finite unions, . It follows that . Since is Lindelof, there exists a countable such that . For each , for some . We claim that is a cover of . To this end, let . Then for some , . This implies that . Thus, the open cover has a countable subcover. This concludes the proof of Theorem 1.
Proof of Theorem 2
Let be a perfect map with . Suppose is paracompact. Let be an open cover of . For each , define as in Lemma 3. By Lemma 3, each is an open subset of . Let . As shown in the proof of Theorem 1, is an open cover of . Since is paracompact, there exists a locally finite open refinement of . Let .
We show three facts about . (1) It is an open cover of . (2) It is a locally finite collection in . (3) It is a refinement of . To see (1), note that is an open cover of . As a result, is an open cover of . To see (2), let . We find an open such that and such that intersects only finitely many elements of . Since is locally finite in , there exists an open such that and such that intersects only finitely many elements of , say, . Let . Clearly, . It can be verified that the only elements of having non-empty intersections with are ,,. To see (3), let where . Then for some and some . We claim that . Let . Then . This implies that . It follows that is a locally finite open refinement of the open cover . This completes the proof of Theorem 2.
Productively Paracompact Spaces
A space is productively paramcompact if is paracompact for every paracompact space . The definition for productively Lindelof can be stated in a similar way. For some reason, the term “productively paracompact” is not used in the literature but is a topic that had been extensively studied. It is also a topic found in this site. The following four classes of spaces are productively paracompact (see here and here).
- Compact spaces
- -compact spaces
- Locally compact spaces
- -locally compact spaces
The proof for compact spaces being productively paracompact given here uses the Tube Lemma (see here). As applications of Theorem 1 and Theorem 2, we use the two theorems to show that compact spaces are both productively Lindelof and productive paracompact.
Theorem 4…. Let any compact space. Then is Lindelof for every Lindelof space .
Theorem 5 ….Let any compact space. Then is paracompact for every paracompact space .
Theorems 4 and 5 are corollaries to the Kuratowski theorem (see here) and Theorems 1 and 2 above. Suppose is compact. Then the projection map from onto is a closed map. The paracompactness of follows whenever is paracompact. The projection map is also perfect since the point inverses are compact due to the compactness of the factor . Then the Lindelofness of follows whenever is Lindelof.
Dan Ma invariant
Daniel Ma invariant
Dan Ma Inverse invariant
Daniel Ma Inverse invariant
Dan Ma perfect map
Daniel Ma perfect map
Dan Ma paracompact space
Daniel Ma paracompact space
Dan Ma Lindelof space
Daniel Ma Lindelof space
Dan Ma topology
Daniel Ma topology
2023 – Dan Ma